(12v^2-8v)/(4v^2-24v)=0

Solution for (12v^2-8v)/(4v^2-24v)=0 equation:

(12v^2-8v)/(4v^2-24v)=0


Domain of the equation: (4v^2-24v)!=0

v∈R


We multiply all the terms by the denominator


(12v^2-8v)=0

We get rid of parentheses

12v^2-8v=0

a = 12; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·12·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*12}=\frac{0}{24}
=0
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*12}=\frac{16}{24}
=2/3
$